Method Calendar.TimeRanges.TimeRange()->offset_to()
- Method
offset_to
 
- intoffset_to(- TimeRange- x)
- Description
- 
Calculates offset to x; this compares two timeranges and gives the integer offset between the two starting points. This is true for suitable a and b: a+a->offset_to(b)==b By suitable means that a and b are of the same type and size. This is obviously true only if a+n has b as a possible result for any n.